To understand the relationship between the surface areas and dimensions of the two rectangular prisms, we can use the formula for the surface area of a rectangular prism, which is:
\[ SA = 2(lw + lh + wh) \]
where \( l \), \( w \), and \( h \) are the dimensions of the prism.
If we denote the dimensions of prism A with \( l_A, w_A, h_A \) and the dimensions of prism B with \( l_B, w_B, h_B \), we know:
\[ SA_A = 25 \quad \text{and} \quad SA_B = 100 \]
The surface area of prism B is 4 times larger than that of prism A:
\[ SA_B = 4 \times SA_A \]
Now, when comparing the dimensions based on the surface area, we observe that if the surface area increases by a factor of \( k \), the linear dimensions of the prism will change by a factor of \(\sqrt{k}\).
In this case, since \( k = 4 \):
\[ \text{If } SA_B = 4 \times SA_A, \text{ then } \text{Dimensions of B are } \sqrt{4} = 2 \text{ times the dimensions of A.} \]
Therefore, the correct statement is:
Since prism B’s surface area is 4 times as large as prism A’s surface area, prism B’s dimensions are twice as large as prism A’s.
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