To find the area of rectangle ABCD, we first need to determine the coordinates of its vertices (A, B, C, and D). The coordinates will involve identifying the x and y values for the corners based on the given values that the x-axis ranges from -7 to 2 and the y-axis ranges from -1 to 8.
Assuming a rectangle where:
- A is at the lower-left corner
- B is at the lower-right corner
- C is at the upper-right corner
- D is at the upper-left corner
Let's assume the rectangle has the following coordinates based on the ranges:
- A(-7, -1)
- B(2, -1)
- C(2, 8)
- D(-7, 8)
Next, calculate the dimensions of the rectangle:
-
Length (horizontal distance between A and B): \[ \text{Length} = x_B - x_A = 2 - (-7) = 2 + 7 = 9 \text{ units} \]
-
Width (vertical distance between A and D): \[ \text{Width} = y_C - y_A = 8 - (-1) = 8 + 1 = 9 \text{ units} \]
Now that we have the length and width, we calculate the area:
\[ \text{Area} = \text{Length} \times \text{Width} = 9 \times 9 = 81 \text{ square units} \]
However, the choices provided are different. It seems there might be an error in the assumption of the rectangle's coordinates or dimensions based on your expected ranges.
Please double-check the location of points A, B, C, and D to ensure they reflect the given coordinates and dimensions or provide additional clarification on the vertices. Without that, we can't definitively choose one of the given options.
In the current context, based on the typical rectangle widths and lengths that can exist given the number lines you specified, the area could come particularly from configurations yielding 16 units² from standard coordinate assumptions that might lie within depicted limits.
If coordinates are accurately confirmed thereafter, the answer remains valid.