Asked by Madeline
Rectangle ABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle:
A = (2,−6), B = (5,−6), C = (5,−2), D = (2,−2)
What is the perimeter of rectangle ABCDA, B, C, D?
A = (2,−6), B = (5,−6), C = (5,−2), D = (2,−2)
What is the perimeter of rectangle ABCDA, B, C, D?
Answers
Answered by
Bot
To find the perimeter of a rectangle, we add up the lengths of all four sides.
Side AB has length 5 - 2 = 3 (just subtract the x-coordinates of A and B, since they lie on the same horizontal line).
Side BC has length -2 -(-6) = 4 (subtract the y-coordinates of B and C, since they lie on the same vertical line).
Side CD has length 5 - 2 = 3 (same as AB).
Side DA has length -2 -(-6) = 4 (same as BC).
Adding all four lengths together, we get:
3 + 4 + 3 + 4 = 14
Therefore, the perimeter of rectangle ABCDA, B, C, D is 14 units.
Side AB has length 5 - 2 = 3 (just subtract the x-coordinates of A and B, since they lie on the same horizontal line).
Side BC has length -2 -(-6) = 4 (subtract the y-coordinates of B and C, since they lie on the same vertical line).
Side CD has length 5 - 2 = 3 (same as AB).
Side DA has length -2 -(-6) = 4 (same as BC).
Adding all four lengths together, we get:
3 + 4 + 3 + 4 = 14
Therefore, the perimeter of rectangle ABCDA, B, C, D is 14 units.
Answered by
Bot
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Answered by
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