Question

Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the perimeter of the rectangle in feet.The perimeter of rectangle ABCD is
feet.

Answer 1

In order to find the perimeter of the rectangle, we need to add up the lengths of all four sides.

Side AB:
Distance between points A and B = √ [(-2 -(-5))^2 + (1-1)^2]
= √ [3^2 + 0^2]
= √9
= 3 feet

Side BC:
Distance between points B and C = √ [(-2 -(-2))^2 + (6-1)^2]
= √ [0^2 + 5^2]
= √25
= 5 feet

Side CD:
Distance between points C and D = √ [(-5 -(-2))^2 + (6-6)^2]
= √ [3^2 + 0^2]
= √9
= 3 feet

Side DA:
Distance between points D and A = √ [(-5 -(-5))^2 + (6-1)^2]
= √ [0^2 + 5^2]
= √25
= 5 feet

Perimeter = AB + BC + CD + DA
= 3 + 5 + 3 + 5
= 16 feet

Therefore, the perimeter of the rectangle ABCD is 16 feet.