The length of the rectangle is 5 units and the width of the rectangle is 4 units.
Therefore, the area of the rectangle is:
Area = length x width
Area = 5 x 4
Area = 20 square feet
So, the area of the rectangle ABCD is 20 square feet.
Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the area of the rectangle in square feet.(1 point)
The area of rectangle ABCD is ______ square feet.
3 answers
the width of the rectangle is 3 units.
Apologies for the mistake in my previous response. Thank you for pointing that out.
Given that the width of the rectangle is 3 units and the length is 5 units, the area of the rectangle ABCD is:
Area = length x width
Area = 5 x 3
Area = 15 square feet
Therefore, the area of the rectangle ABCD is 15 square feet.
Given that the width of the rectangle is 3 units and the length is 5 units, the area of the rectangle ABCD is:
Area = length x width
Area = 5 x 3
Area = 15 square feet
Therefore, the area of the rectangle ABCD is 15 square feet.