Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the perimeter of the rectangle in feet.(1 point)The perimeter of rectangle ABCD is 14 feet.

Answer 1

To find the perimeter of the rectangle, we need to find the distance between each pair of consecutive points and then add them all together.

The distance formula between two points (x1, y1) and (x2, y2) is given by d = sqrt((x2 - x1)^2 + (y2 - y1)^2).

Using this formula, we can find the distances between the points:

AB: sqrt((-2 - (-5))^2 + (1 - 1)^2) = sqrt(3^2 + 0) = 3 feet
BC: sqrt((-2 - (-2))^2 + (6 - 1)^2) = sqrt(0 + 5^2) = 5 feet
CD: sqrt((-5 - (-2))^2 + (6 - 6)^2) = sqrt(3^2 + 0) = 3 feet
DA: sqrt((-5 - (-5))^2 + (1 - 6)^2) = sqrt(0 + 5^2) = 5 feet

Now, we add the distances together to find the perimeter:
Perimeter = 3 + 5 + 3 + 5 = 16 feet

Therefore, the perimeter of rectangle ABCD is 16 feet.