Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the perimeter of the rectangle in feet.(1 point)

Answer 1

To find the perimeter of the rectangle, we need to add up the lengths of all four sides.

Using the distance formula, the length of side AB is:
AB = √[(-2 - (-5))^2 + (1 - 1)^2]
AB = √[3^2 + 0]
AB = √9
AB = 3

Similarly, the length of side BC is:
BC = √[(-2 - (-2))^2 + (6 - 1)^2]
BC = √[0 + 5^2]
BC = √25
BC = 5

Since AB and CD are parallel and equal in length, the length of side CD is also 3.

Similarly, the length of side AD is:
AD = √[(-5 - (-5))^2 + (6 - 1)^2]
AD = √[0 + 5^2]
AD = √25
AD = 5

So, the perimeter of the rectangle is:
Perimeter = AB + BC + CD + DA
Perimeter = 3 + 5 + 3 + 5
Perimeter = 16

Therefore, the perimeter of the rectangle is 16 feet.