Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the perimeter of the rectangle in feet.(1 point)

Question

The perimeter of rectangle ABCD is [___] feet.

Answer 1

To find the perimeter of the rectangle, we need to calculate the distance between each pair of consecutive points A, B, C, D.

1. From point A to point B:
Distance = √((-2 - (-5))^2 + (1 - 1)^2)
Distance = √(3^2 + 0)
Distance = √9
Distance = 3 feet

2. From point B to point C:
Distance = √((-2 - (-2))^2 + (6 - 1)^2)
Distance = √(0 + 5^2)
Distance = √25
Distance = 5 feet

3. From point C to point D:
Distance = √((-5 - (-2))^2 + (6 - 6)^2)
Distance = √(3^2 + 0)
Distance = √9
Distance = 3 feet

4. From point D to point A:
Distance = √((-5 - (-5))^2 + (1 - 6)^2)
Distance = √(0 + 5^2)
Distance = √25
Distance = 5 feet

Finally, add up all the distances to get the perimeter of the rectangle:
Perimeter = 3 + 5 + 3 + 5 = 16 feet

Therefore, the perimeter of rectangle ABCD is 16 feet.