Rectangle ABCD has vertices point A (-5, 1), point B (-2, 1), point C (-2, 6), and point D (-5, 6). Find the perimeter of the rectangle in feet. (1 point)

Answer 1

To find the perimeter of the rectangle, we need to find the distance between each pair of consecutive vertices and then add them up.

AB:
Distance = sqrt((-2 - (-5))^2 + (1 - 1)^2)
Distance = sqrt(3^2 + 0^2)
Distance = sqrt(9)
Distance = 3 units

BC:
Distance = sqrt((-2 - (-2))^2 + (6 - 1)^2)
Distance = sqrt(0^2 + 5^2)
Distance = sqrt(25)
Distance = 5 units

CD:
Distance = sqrt((-5 - (-2))^2 + (6 - 6)^2)
Distance = sqrt(3^2 + 0^2)
Distance = sqrt(9)
Distance = 3 units

DA:
Distance = sqrt((-5 - (-5))^2 + (6 - 1)^2)
Distance = sqrt(0^2 + 5^2)
Distance = sqrt(25)
Distance = 5 units

Now, add up the distances to find the perimeter of the rectangle:
Perimeter = AB + BC + CD + DA
Perimeter = 3 + 5 + 3 + 5
Perimeter = 16 units

Since the units were not specified, we will assume that they are in feet, so the perimeter of the rectangle is 16 feet.