That is correct.
a(u) = 32
v(u) = 32u + Vo
v(t) - v(0) = 32t
Recall that the acceleration a(t) of a particle moving along a straight line is the instantaneous rate of change of the velocity v(t); that is,
a(t) = d/dt v(t)
Assume that a(t) = 32 ft/s². Express the cumulative change in velocity during the interval [0, t] as a definite integral, and compute the integral.
So far I got:
v(t) - v(0) = the integral from 0 to t of a(u)du, but im not sure where to go from there.
Thank you so much for your help!!
1 answer