Rearrange the following formula A=BC−D to solve for B. Make sure to show each step. Make sure your step matches the explanation on the right! (1 point)

3 answers

To rearrange the formula \( A = BC - D \) to solve for \( B \), we can follow these steps:

  1. Add \( D \) to both sides: This helps isolate the term with \( B \). \[ A + D = BC \]

  2. Divide both sides by \( C \): This will give us \( B \) by itself. \[ B = \frac{A + D}{C} \]

So, the rearranged formula to solve for \( B \) is: \[ B = \frac{A + D}{C} \]

Now we have successfully solved for \( B \) in the equation \( A = BC - D \).

instead of dividing C from both sides, multiply it

Certainly! If we want to rearrange the formula \( A = BC - D \) to solve for \( B \) and prefer to multiply instead of dividing by \( C \), we can do the following:

  1. Add \( D \) to both sides: This step isolates the term containing \( B \). \[ A + D = BC \]

  2. Multiply both sides by \( C \): This changes the equation to encompass \( B \) directly without division at this step. \[ C(A + D) = BC \cdot C \] However, this step isn’t necessary for isolating \( B \). You actually want to isolate \( B \).

So instead of multiplying, we go back to:

  • Add \( D \): \[ A + D = BC \]

  • Divide both sides by \( C \) to isolate \( B \): \[ B = \frac{A + D}{C} \]

If you specifically want to maintain the multiplication aspect, you still must eventually divide to fully isolate \( B \). Thus, the effective solution remains: \[ B = \frac{A + D}{C} \]

If you had further modifications in mind, please specify!