Rearrange for J;
n=(2J+1)exp(-(BJ(J+1))/(KT))
where T, B and K are constants
1 answer
This questions was posted and answered about a day ago. If you posted it, look for previous posts with your name.
n=(2J+1)exp(-(BJ(J+1))/(KT))
where T, B and K are constants
1 answer