(3n-1)!/(3n+2)! = 1/((3n+2)(3n+1)(3n)) < 1/n^3
so it converges
Really stuck
asubn= (3n-1)!/(3n+2)!
Determine whether the sequence converges or diverges
1 answer
asubn= (3n-1)!/(3n+2)!
Determine whether the sequence converges or diverges
1 answer