This problem has been posted a number of times with varying parts of what I suppose was the initial entire question. Here is a way to get to the site; I can't copy it to this page. Click on the PDF file of Chemistry 112.
http://www.google.com/search?q=potassium+hexaoxalatoferrate%28III%29&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a
Really need help on figuring out the formula for Iron Complex.
The question was:
4.0 g of ferrous ammonium sulphate, FeS04(NH4)2*SO4*6H20, is used. The oxalate is in excess, calculate the theoretical yield of the iron complex.
I got the moles of ferrous ammonium sulfate but I am stuck on how to figure out the balanced equation and the formula for the iron complex.
Wouldn't it be just FeC2O4? Since Fe has a 2+ charge and C2O4 has a 2- charge?
I've looked around in the internet and their answer was this: [Fe(C2O4)3]3-
I don't understand.
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