To complete the table using the function \( k = 7d \), we will plug in the values of \( d \) for each day into the equation to find \( k \).
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For \( d = 1 \): \[ k = 7 \times 1 = 7 \]
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For \( d = 2 \): \[ k = 7 \times 2 = 14 \]
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For \( d = 3 \): \[ k = 7 \times 3 = 21 \quad \text{(already given)} \]
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For \( d = 4 \): \[ k = 7 \times 4 = 28 \]
Now, we can fill in the table:
\[ \begin{array}{|c|c|} \hline d & k \ \hline 1 & 7 \ 2 & 14 \ 3 & 21 \ 4 & 28 \ \hline \end{array} \]
So the completed table is:
\[ \begin{array}{|c|c|} \hline d & k \ \hline 1 & 7 \ 2 & 14 \ 3 & 21 \ 4 & 28 \ \hline \end{array} \]