I'll do one of these. I don't see wht you can't do the others yourself. Give is a try.
1. The truck has a velocity of 8.30 m/s and comes to a stop in 15.0 s.
vi (inital) = 8.30 m/s
vf (final) = 0
pi (inital momentum) = 2840*8.3 = 23,572 kg*m/s
pf = 0
Impulse = pf - pi = -23672 kg*m/s
Force required = (impluse/time) =
-23672/15 = -1571 newtons
It is negative becasue the force must oppose the motion.
Read each statement below. For each situation, calculate vi, vf, pi, pf, the impulse vector Ft, and the amount of force needed for the change to occur. All situations refer to a truck with a mass of 2840 kg.
1. The truck has a velocity of 8.30 m/s and comes to a stop in 15.0 s.
2. The truck, initially at rest, reaches a velocity of 8.30 m/s in 20.0 s.
3. The truck is at rest. In 5.00 s, the truck backs up to a speed of 1.38 m/s.
4. The truck is moving backward with a velocity of 1.38 m/s and comes to a stop in 5.00 s.
2 answers
-1571 n