Let's cal the two unknown dimensions n and m, then 10nm=360 hence n*m=36
36=3*3*2*2 hence there are 5 ways to choose the dimensions.
Raymond wants to make a box that has a volume of 360 cubic inches. He wants the height to be 10 in. and the other dimensions to be whole numbers of inches. how many different sized boxes can he make?
3 answers
Volume=L×w×h=360
L×w×10=360
L×w=36/10
L×w=36
You would have to find all the possible factors of 36
We include
1,2,3,4,6,9,12,18,36
L×w=36×1
L×w=9×4
L×w=18×2
If the L=36 ,w=1 & h=10
L×w×h=36×10×1=360✓
So what possible combination can you see? knowing that when multiplied gives you 36... If the L>w
??
L×w×10=360
L×w=36/10
L×w=36
You would have to find all the possible factors of 36
We include
1,2,3,4,6,9,12,18,36
L×w=36×1
L×w=9×4
L×w=18×2
If the L=36 ,w=1 & h=10
L×w×h=36×10×1=360✓
So what possible combination can you see? knowing that when multiplied gives you 36... If the L>w
??
Discovered a typo
L×w×10=360
L×w=360/10=36
But nothing changes just and error
L×w×10=360
L×w=360/10=36
But nothing changes just and error