(3∛12 - 8)/(∛9-∛6)
since a^3-b^3 = (a-b)(a^2+ab+b^2), multiply top and bottom by
(∛9^2 + ∛(9*6) + ∛6^2)
then you have
(∛36 - 6∛2 - 6∛3)/3
Rationalize the denominator of (3 * cube root of 12 - 8) / (cube root of 9 - cube root of 6).
Please show steps and the full process to rationalize.
1 answer