To find the intersection point of the given equations, we analyze the equations provided:
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The first equation is \( y = -3 \). This is a horizontal line where the value of \( y \) is always -3.
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The second equation is \( y = x - 0.8 \). This is a straight line with a slope of 1 and a y-intercept of -0.8.
To find the intersection of these two lines, we can set their y-values equal to each other:
\[ -3 = x - 0.8 \]
Now, solve for \( x \):
\[ x - 0.8 = -3 \] \[ x = -3 + 0.8 \] \[ x = -2.2 \]
Thus, the intersection point is approximately \((-2.2, -3)\).
Among the answer choices provided:
- \((–3.2, –3)\)
- \((–2.9, –3)\)
- \((–2.2, –3)\)
- \((–1.9, –3)\)
The best approximation for the solution to this system of equations is:
\(\boxed{(–2.2, –3)}\).