Ran had some boxes of biscuits for sale. He sold 140 boxes on Friday. He sold 1/4 of the remaining boxes of biscuits on Saturday. Then he had 2/5 of the total number of boxes of biscuits left, how many boxes of biscuits did he have at first?

Answer 1

The name is supposed to be Raj not Ran

Answer 2

300

Answer 3

To determine how many boxes of biscuits Raj initially had, let's go backwards.

Raj still had two-fifths of the total number of biscuit boxes after Saturday's sales. This indicates that before Saturday's sales, he still owned 3/5 of the boxes.

Let's refer to Raj's initial stock of biscuits boxes as having "x" totals. He has x–140 boxes left after selling 140 boxes on Friday. Later, on Saturday, he sold one-fourth of the unsold boxes. This indicates that on Saturday, he sold (1/4)(x - 140) boxes. As a result, following Saturday's sales, he still owned 3/4 of the remaining boxes.

For this, we may construct an equation as follows:

3/4(x - 140) = 2/5x

To eliminate the fractions, multiply both sides by 20 (the least common multiple of 4 and 5), and the result is:

15(x - 140) = 8x

Increasing the brackets results in:

15x - 2100 = 8x

8x is subtracted from both sides to yield:

7x - 2100 = 0

2100 added to both sides gives us:

7x = 2100

When we multiply both sides by 7, we get:

x = 300

Raj therefore started out with 300 boxes of biscuits.