RAM of copper (II) tetraoxosulphate (VI) pentahydrate.

Answer 1

The molar mass of copper (II) tetraoxosulphate (VI) pentahydrate can be calculated as follows:

Copper (II) tetraoxosulphate (VI):
- Copper (II) ion (Cu2+): 1 x 63.55 g/mol = 63.55 g/mol
- Tetraoxosulphate (VI) ion (SO4^2-): 1 x 96.06 g/mol = 96.06 g/mol

Pentahydrate:
- Water (H2O): 5 x 18.02 g/mol = 90.1 g/mol

Combining the above components, the molar mass of copper (II) tetraoxosulphate (VI) pentahydrate is:
Molar mass = 63.55 + 96.06 + 90.1 = 249.71 g/mol

Therefore, the RAM of copper (II) tetraoxosulphate (VI) pentahydrate is approximately 249.71 g/mol.