Let the horizontal distance from the base of the building to where Ajay is standing be denoted as x.
Using trigonometry, we can set up the following equation:
tan(50°) = 25/x
Solving for x:
x = 25/tan(50°)
x ≈ 19.1
Therefore, the horizontal distance from the base of the building to where Ajay is standing is approximately 19.1 meters.
Ralph is on the roof of a building, while his friend Ajay is on the ground. Ralph can see Ajay at a
50° angle of depression. The vertical height of the building is 25 m. What is the horizontal distance from the base of the building to where Ajay is standing? Round your answer to one decimal.
1 answer
1 answer