To clear the fractions in the equation \( y = \frac{23}{1}x + 14 \), we can multiply the entire equation by the denominator in question, which is \(1\) in this case. However, because there are no fractions present, we wouldn't need to multiply by any number.
If we interpret the question as needing to express the equation in standard form \( Ax + By = C \), we would rather manipulate the existing equation directly:
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Start with the equation:
\[ y = 23x + 14 \] -
Rearrange it to standard form by moving all terms to one side:
\[ -23x + y = 14 \] or equivalently, \[ 23x - y = -14 \]
Since there are no fractions in this equation, you do not need to multiply by any specific number to clear fractions.
Therefore, none of the options given (4, 12, 3, 6) are actually necessary to clear fractions since there are none in the original equation.
If you were specifically looking for a number to express it in standard form, but subject to these options, any non-zero coefficient could technically work, but the correct answer is simply that multiplication by a number isn't required here.