To clear the fractions in the equation \( y = \frac{2}{3}x + \frac{1}{4} \), we can find the least common multiple (LCM) of the denominators, which are 3 and 4.
The LCM of 3 and 4 is 12. By multiplying the entire equation by 12, we can eliminate the fractions.
Let's multiply each term in the equation by 12:
\[ 12y = 12\left(\frac{2}{3}x\right) + 12\left(\frac{1}{4}\right) \]
Calculating each term:
- \( 12y \) remains \( 12y \).
- For \( 12 \cdot \frac{2}{3}x \): \[ 12 \cdot \frac{2}{3} = 4 \cdot 2 = 8 \Rightarrow 8x \]
- For \( 12 \cdot \frac{1}{4} \): \[ 12 \cdot \frac{1}{4} = 3 \]
Putting it all together, we have: \[ 12y = 8x + 3 \]
Thus, if Rahul multiplies the equation by 12, the fractions will be cleared, and the equation can now be rewritten in a standard form.