Radio waves (419m) from a station travel along two paths from the transmitter to a house. The first path is direct, 27km, and the second path is by reflection from a mountain directly behind the house. No phase change occurs upon reflection from the mountain. What minimum distance from the mountain to the house cases destructive interference?

1 answer

The waves must be out of phase by half a wavelength for destructive interference, so the path difference Δ =2•s is equal to (n + ½)λ, or s = λ/4=419/4 =104.75 m.