To solve the radical equation \( \sqrt[3]{400 - 6x} = 4 \), we can start by isolating the radical and then cubing both sides to eliminate the radical.
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Cube both sides: \[ 400 - 6x = 4^3 \] \[ 400 - 6x = 64 \]
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Now, isolate \( x \): \[ -6x = 64 - 400 \] \[ -6x = -336 \]
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Divide both sides by \(-6\): \[ x = \frac{-336}{-6} \] \[ x = 56 \]
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Therefore, our solution is \( x = 56 \).
Now, substituting back the value into the original equation can confirm this result:
- Original equation: \(\sqrt[3]{400 - 6(56)} = 4\)
- Calculation: \(\sqrt[3]{400 - 336} = \sqrt[3]{64} = 4\), which is correct.
So the final answer is: \[ \text{x equals } 56 \]