Radical ((1-sinx)/(1+sinx))= (1-sinx)/cosx (absolute)
Simplify
2 answers
Identity the identity i meant
Note that if you multiply on the left inside the radical, by (1-sinx)/(1-sinx), you have
√((1-sinx)^2/(1-sin^2(x))
That should get you most of the way there, since √x^2 = |x|
√((1-sinx)^2/(1-sin^2(x))
That should get you most of the way there, since √x^2 = |x|