Asked by TJ
_____R____________
| | |
|+ | XC
E1 XL |
|- | |+
| | E2
___________________-
Z1 = R= 4 ohms <0 4+-j0
Z2 = XL= 6 ohms <90. 0+j6
Z3 = XC=8 ohms <-90. 0-j8
E1= 10 v < 0. 10 +j0
E2= 40 v < 60. 20+j34.64
Please help me find the current up through R using mesh analysis.
I am having trouble because of the voltage polar angles.
My derivative is
(Z1+Z2) -Z2
-Z2 (Z2+Z3)
= Z1Z2 + Z1Z3 + Z2Z3
I1= E1. -Z2
-E2. Z2+Z3
=Z2(E1-E2) +Z3E1/D
I2=Z1+Z2. E1
-Z2. -E2
=-Z2(e1+e2)-Z1E2/D
Once the numbers and j's and polar angles get thrown around I have trouble keeping track. I'm not even sure if my I1 or I2 numerator is distributed correctly.
| | |
|+ | XC
E1 XL |
|- | |+
| | E2
___________________-
Z1 = R= 4 ohms <0 4+-j0
Z2 = XL= 6 ohms <90. 0+j6
Z3 = XC=8 ohms <-90. 0-j8
E1= 10 v < 0. 10 +j0
E2= 40 v < 60. 20+j34.64
Please help me find the current up through R using mesh analysis.
I am having trouble because of the voltage polar angles.
My derivative is
(Z1+Z2) -Z2
-Z2 (Z2+Z3)
= Z1Z2 + Z1Z3 + Z2Z3
I1= E1. -Z2
-E2. Z2+Z3
=Z2(E1-E2) +Z3E1/D
I2=Z1+Z2. E1
-Z2. -E2
=-Z2(e1+e2)-Z1E2/D
Once the numbers and j's and polar angles get thrown around I have trouble keeping track. I'm not even sure if my I1 or I2 numerator is distributed correctly.
Answers
Answered by
TJ
Okay well the circuit picture didn't figure very well. R is in series with e1 and XL
XL is in series on the other side with XC and e2
XL is in series on the other side with XC and e2
Answered by
Henry
I = VR/R = 10/4 = 2.5A. = Current through all components(R,L, and C).
VL = I*XL = 2.5 * 6 = j15.0 Volts.
Vc = I*Xc = 2.5 * 8 = -j20.0 Volts.
Z = R + j(XL-Xc)) = 4 + j(6-8) =
4 - j2 = 4.47 Ohms[-26.6o].
Es = I*Z = 2.5 * 4.47 = 11.2 Volts.
Pf = Cos(-26.6) = 0.894 = Power factor.
P = I^2*R = 2.5^2 * 4 = 25 Watts.
VL = I*XL = 2.5 * 6 = j15.0 Volts.
Vc = I*Xc = 2.5 * 8 = -j20.0 Volts.
Z = R + j(XL-Xc)) = 4 + j(6-8) =
4 - j2 = 4.47 Ohms[-26.6o].
Es = I*Z = 2.5 * 4.47 = 11.2 Volts.
Pf = Cos(-26.6) = 0.894 = Power factor.
P = I^2*R = 2.5^2 * 4 = 25 Watts.
Answered by
Henry
Note: If the voltage across the resistor
is incorrect, all voltages will be wrong.
is incorrect, all voltages will be wrong.
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