R is the first quadrant region enclosed by the x-axis, the curve y = 2x + a, and the line x = a, where a > 0. Find the value of a so that the area of the region R is 18 square units.

Answer 1

even without calculus, this one is easy. The x-intercept of y=2x+a is x = -a/2

So, you have a triangle with base 3a/2 and height 3a, so the area is 9a^2/4.

If 9a^2/4 = 18, a = √8

check:

∫[-a/2,a] 2x+a dx = 9a^2/4

Answer 2

I did a(a+2a+a)/2=18
and got 3 but idk if that's right

Answer 3

the answer choices are
A. 3
B. 3.772
C. 4.242
D. 9

Answer 4

Where did steve get the triangle parts from?? :(

Answer 5

i have never gotten one straightforward correct answer from this guy steve

Answer 6

Look at the graph and you'll see the triangle and rectangle. It is baseline geometry problem. The answer is 3