Using the power rule of integration, we can integrate (x^{-1/3}) dx:
∫(x^{-1/3})dx = (x^{2/3})/(2/3) + C
Simplifying, we get:
∫(x^{-1/3})dx = (3/2)x^{2/3} + C
Therefore, the result of the integral ∫(h(x−x^{1/3}))dx is:
∫(h(x - x^{1/3}))dx = h(3/2)x^{2/3} - h(2/5)x^{5/3} + C
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