To determine if triangles \( \triangle FHG \) and \( \triangle PRQ \) are similar, we can use the AA (Angle-Angle) Similarity Theorem, which states that if two angles in one triangle are equal to two angles in another triangle, the triangles are similar.
You provided the following angle measures:
- \( m\angle H = 38^\circ \)
- \( m\angle P = 38^\circ \)
- \( m\angle G = 41^\circ \)
- \( m\angle Q = 41^\circ \)
We see that:
- \( \angle H \) corresponds to \( \angle P \) (both are \( 38^\circ \)).
- \( \angle G \) corresponds to \( \angle Q \) (both are \( 41^\circ \)).
Since we have two pairs of corresponding angles that are equal, we conclude that \( \triangle FHG \sim \triangle PRQ \) by the AA Similarity Theorem.
Thus, the correct response is:
yes because of the AA Similarity Theorem.