r^2+8r=48

First bring the 48 to the other side of the equation

r^2+8r-48=0

Now you can use the quadratic formula.

x=-b+-sqrt(b^2-(4ac))
¯¯¯¯¯¯¯2a¯¯¯¯¯¯¯¯¯

So...
a=1
b=8
c=-48

Now just plug the numbers into the quadratic equation and get your two answers.

The answers are: x=-12 and x=4

Feel free to ask if you need any more help. :-)

Similar Questions
    1. answers icon 2 answers
  1. fter subtracting x from each side, the equation is 4y=10−x. You can rearrange the terms on the right side so the equation is
    1. answers icon 1 answer
  2. h(x)= 3x+2/7x-6find the inverse of h^-1(x) h^-1(x) = ? Would I solve it like this h(x)= 3x+2/7x-6 7xy-6y=3x+2 (bring 7x-6 to
    1. answers icon 2 answers
  3. (x/x-2)+(x-1/x+1)=-1So far I was able to get it to x + (x-1) = -(x-2)(x+1) through cross multiplying, but I'm kinda lost with
    1. answers icon 5 answers
more similar questions