To find the area of an isosceles trapezoid, you can use the formula:
\[ \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h \]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height of the trapezoid.
In this case:
- \( b_1 = 1.5 \) meters (the shorter base),
- \( b_2 = 2 \) meters (the longer base),
- \( h = 1 \) meter (the height).
Now, plugging in the values:
\[ \text{Area} = \frac{1}{2} \times (1.5 + 2) \times 1 \] \[ = \frac{1}{2} \times 3.5 \times 1 \] \[ = \frac{3.5}{2} \] \[ = 1.75 , \text{square meters} \]
Therefore, the area of the table top is \( \boxed{1.75} \) square meters.
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