Question

Write the standard form of the equation of a circle with a radius of 2 and center at left parenthesis 4 comma negative 5 right parenthesis.
(1 point)
Responses

left parenthesis x plus 4 right parenthesis squared plus left parenthesis y plus 5 right parenthesis squared equals 4
Image with alt text: left parenthesis x plus 4 right parenthesis squared plus left parenthesis y plus 5 right parenthesis squared equals 4

left parenthesis x minus 4 right parenthesis squared plus left parenthesis y plus 5 right parenthesis squared equals 4
Image with alt text: left parenthesis x minus 4 right parenthesis squared plus left parenthesis y plus 5 right parenthesis squared equals 4

left parenthesis x plus 4 right parenthesis squared plus left parenthesis y minus 5 right parenthesis squared equals 4
Image with alt text: left parenthesis x plus 4 right parenthesis squared plus left parenthesis y minus 5 right parenthesis squared equals 4

left parenthesis x minus 4 right parenthesis squared plus left parenthesis y minus 5 right parenthesis squared equals 4

1 answer

To write the equation of a circle in standard form, we use the formula:

\((x - h)^2 + (y - k)^2 = r^2\)

where \((h, k)\) is the center of the circle and \(r\) is the radius.

Given:

  • Center: \((4, -5)\)
  • Radius: \(2\)

Substituting these values into the formula:

\[ (x - 4)^2 + (y + 5)^2 = 2^2 \] \[ (x - 4)^2 + (y + 5)^2 = 4 \]

Therefore, the standard form of the equation of the circle is:

\[ (x - 4)^2 + (y + 5)^2 = 4 \]

The correct response is:

left parenthesis x minus 4 right parenthesis squared plus left parenthesis y plus 5 right parenthesis squared equals 4