There are two solid boundary lines, one with a y-intercept at 4 and a slope of 2, and the other with a y-intercept at 2 and a slope of -1. The shaded region is above the first boundary line and below the second boundary line.
The correct system of inequalities that represents this graph is:
y ≤ 2x + 4
y ≥ -x + 2
Question
Which of the following systems of inequalities represents the graph?
A coordinate plane containing a solid boundary line with a y-intercept at 4, a slope of 2, and shading above the boundary line. There is a second dashed boundary line with a y-intercept at 2, a slope of negative 1, and shading below the boundary line. The overlapping shaded region contains points such as negative 4, 0 and negative 5, 2.A solid line passes through the points left-parenthesis 0 comma 4 right-parenthesis and left-parenthesis 2 comma 8 right-parenthesis. The region above the line is shaded red. A dotted line passes through the points left-parenthesis 0 comma 2 right-parenthesis and left-parenthesis 2 comma 0 right-parenthesis. The region below the line is shaded blue. A region of the coordinate plane is shaded both red and blue.
(1 point)
Responses
y ≤ 2x + 4
y ≥ –x + 2
y ≤ 2 x + 4 y ≥ –x + 2
2x – y ≥ 4
y < –x + 2
2 x – y ≥ 4 y < –x + 2
y ≥ 2x + 4
–x + y ≤ 2
y ≥ 2 x + 4 – x + y ≤ 2
–2x + y ≥ 4
x + y < 2
1 answer
1 answer