To solve the inequality \( x + \frac{1}{3} > 4 \), we first simplify it:
-
Subtract \(\frac{1}{3}\) from both sides: \[ x > 4 - \frac{1}{3} \]
-
Convert 4 into a fraction: \[ 4 = \frac{12}{3} \] Therefore, \[ x > \frac{12}{3} - \frac{1}{3} = \frac{11}{3} \]
Now convert \(\frac{11}{3}\) to a mixed number: \[ \frac{11}{3} = 3 \frac{2}{3} \]
In decimal form, \(\frac{11}{3} \approx 3.67\) or \(3.666...\).
The solution to the inequality is \( x > \frac{11}{3} \) or \( x > 3 \frac{2}{3} \).
Graph Representation:
On a number line:
- You would have an open circle at \( \frac{11}{3} \) (which is the same as \(3 \frac{2}{3}\)).
- The line should extend to the right toward positive infinity, indicating all numbers greater than \( \frac{11}{3} \).
Correct Option:
From the provided responses, the correct option would be:
A number line with arrows at both the ends ranges from negative 10 to 10 in unit increments. An open circle is marked on the tick line above \( 3 \frac{2}{3} \). A line is drawn from the circle toward 10 with an arrow at the end.