To determine which equation has a solution different from the rest, we can solve each equation for x.
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Equation: -17x - 34 = 14 \[ -17x = 14 + 34 \] \[ -17x = 48 \] \[ x = -\frac{48}{17} \approx -2.82 \]
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Equation: \( -\frac{1}{7}x - \frac{3}{4} = \frac{1}{4} \) \[ -\frac{1}{7}x = \frac{1}{4} + \frac{3}{4} \] \[ -\frac{1}{7}x = 1 \] \[ x = -7 \]
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Equation: \( 12x - 3 = 12 \) \[ 12x = 12 + 3 \] \[ 12x = 15 \] \[ x = \frac{15}{12} = \frac{5}{4} = 1.25 \]
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Equation: \( \frac{1}{2}x - 3 = \frac{1}{2} \) \[ \frac{1}{2}x = \frac{1}{2} + 3 \] \[ \frac{1}{2}x = \frac{1}{2} + \frac{6}{2} = \frac{7}{2} \] \[ x = 7 \]
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Equation: -0.35x - 0.52 = 1.93 \[ -0.35x = 1.93 + 0.52 \] \[ -0.35x = 2.45 \] \[ x = -\frac{2.45}{0.35} \approx -7 \]
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Equation: 34x + 5 = -14 \[ 34x = -14 - 5 \] \[ 34x = -19 \] \[ x = -\frac{19}{34} \approx -0.56 \]
Now, we summarize the solutions:
- 1: \( x \approx -2.82 \)
- 2: \( x = -7 \)
- 3: \( x = 1.25 \)
- 4: \( x = 7 \)
- 5: \( x \approx -7 \)
- 6: \( x \approx -0.56 \)
The solutions for equations 2 and 5 are both -7, but their other values are all different from each other.
Thus, the equation that has a solution different from the rest is:
Equation 3: \( 12x - 3 = 12 \) which leads to \( x = 1.25 \).