Question
Which factor is not needed when calculating the velocity of a satellite orbiting a planet?(1 point)
Responses
the universal gravitational constant
the universal gravitational constant
the mass of the planet
the mass of the planet
the orbital radius of the satellite
the orbital radius of the satellite
the mass of the satellite
the mass of the satellite
5 answers
the mass of the satellite
Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a low Earth orbit?(1 point)
Responses
v=Gmp(200 km)−−−−−−√
v=Gmp(200 km)−−−−−−√
v=1(7,000 km)Gmp−−−−√
v=1(7,000 km)Gmp−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=1(200 km)Gmp−−−−√
Responses
v=Gmp(200 km)−−−−−−√
v=Gmp(200 km)−−−−−−√
v=1(7,000 km)Gmp−−−−√
v=1(7,000 km)Gmp−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=Gmp(7,000 km)−−−−−−−√
v=1(200 km)Gmp−−−−√
v=Gmp(7,000 km)−−−−−−−√
Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a geostationary orbit?(1 point)
Responses
v=Gmp(48,115 km)−−−−−−−−√
v=Gmp(48,115 km)−−−−−−−−√
v=Gmp(7,324 km)−−−−−−−√
v=Gmp(7,324 km)−−−−−−−√
v=Gmp(15,522 km)−−−−−−−−√
v=Gmp(15,522 km)−−−−−−−−√
v=Gmp(42,164 km)−−−−−−−−√
Responses
v=Gmp(48,115 km)−−−−−−−−√
v=Gmp(48,115 km)−−−−−−−−√
v=Gmp(7,324 km)−−−−−−−√
v=Gmp(7,324 km)−−−−−−−√
v=Gmp(15,522 km)−−−−−−−−√
v=Gmp(15,522 km)−−−−−−−−√
v=Gmp(42,164 km)−−−−−−−−√
v=Gmp(42,164 km)−−−−−−−−√