Question: When 1.97 grams of Pb(OH)2(s) is added to 1.00 liter of pure water at 25 C a saturated solution (some solid is present) is formed that has a pH of 8.97. Compute the Ksp value for Pb(OH)2 using the data.
[OH]= 9.334e-6 and the [Pb^+2]= 9.334e-6/2= 4.667e-6. So the ksp= 9.334e-6 * 4.667e-6= 4.356e-11
3 answers
You didn't square the OH^-
Right! so after i square it the correct answer would be 4.066e-16
I think so. Look up Ksp in your set of Ksp tables and see how close that comes. I have an old quant book (about 15 years old) that shows 2.5 x 10^-16.
4 answers