Question

What is the momentum of a 15 gram (0.015kg) bullet traveling at 280 m/s. The momentum of the bullet is _______ kg m/s

1 answer

The momentum \( p \) of an object is calculated using the formula:

\[ p = m \cdot v \]

where:

  • \( m \) is the mass of the object in kilograms,
  • \( v \) is the velocity of the object in meters per second.

For the bullet:

  • \( m = 0.015 \) kg (since 15 grams is equal to 0.015 kg),
  • \( v = 280 \) m/s.

Now, we can calculate the momentum:

\[ p = 0.015 , \text{kg} \cdot 280 , \text{m/s} \]

\[ p = 4.2 , \text{kg m/s} \]

Thus, the momentum of the bullet is 4.2 kg m/s.