The zeroes of the function can be found by setting y=0 and solving for x.
0 = x(x + 2)(x + 5)
Since the product of the factors equals zero, this means that one or more of the factors must be zero.
Setting each factor equal to zero and solving:
x = 0, x + 2 = 0, x + 5 = 0
Solving these equations we get:
x = 0, x = -2, x = -5
Therefore, the zeroes of the function are -2, -5, and 0.
To graph the function, we can plot these zeros on the x-axis (-2, -5, and 0) and observe the behavior of the function.
The graph will have x-intercepts at -2, -5, and 0.
Question What are the zeroes of the function? Graph the function. y = x(x + 2)(x + 5) (1 point) Responses –2, –5, 2
3 answers
What are the zeroes of the function? Graph the function.
y = x(x + 2)(x + 5)
(1 point)
Responses
–2, –5
assessment question 2 answer b
–2, –5 Image with alt text: assessment question 2 answer b
0, 2, 5
assessment question 2 answer aAs x increases, the function first increases, then decreases, and then increases. The function passes through the points left-parenthesis 0 comma 0 right-parenthesis, left-parenthesis 2 comma 0 right-parenthesis, and left-parenthesis 5 comma 0 right-parenthesis.
0, 2, 5 Image with alt text: assessment question 2 answer a As x increases, the function first increases, then decreases, and then increases. The function passes through the points left-parenthesis 0 comma 0 right-parenthesis, left-parenthesis 2 comma 0 right-parenthesis, and left-parenthesis 5 comma 0 right-parenthesis.
0, –2, –5
assessment question 2 answer dAs x increases, the function first increases, then decreases, and then increases. The graph of the function passes through the points left-parenthesis negative 5 comma 0 right-parenthesis, left-parenthesis negative 2 comma 0 right-parenthesis, and left-parenthesis 0 comma 0 right-parenthesis.0, –2, –5 Image with alt text: assessment question 2 answer d As x increases, the function first increases, then decreases, and then increases. The graph of the function passes through the points left-parenthesis negative 5 comma 0 right-parenthesis, left-parenthesis negative 2 comma 0 right-parenthesis, and left-parenthesis 0 comma 0 right-parenthesis.
–2, –5, 2
assessment question 2 answer c
y = x(x + 2)(x + 5)
(1 point)
Responses
–2, –5
assessment question 2 answer b
–2, –5 Image with alt text: assessment question 2 answer b
0, 2, 5
assessment question 2 answer aAs x increases, the function first increases, then decreases, and then increases. The function passes through the points left-parenthesis 0 comma 0 right-parenthesis, left-parenthesis 2 comma 0 right-parenthesis, and left-parenthesis 5 comma 0 right-parenthesis.
0, 2, 5 Image with alt text: assessment question 2 answer a As x increases, the function first increases, then decreases, and then increases. The function passes through the points left-parenthesis 0 comma 0 right-parenthesis, left-parenthesis 2 comma 0 right-parenthesis, and left-parenthesis 5 comma 0 right-parenthesis.
0, –2, –5
assessment question 2 answer dAs x increases, the function first increases, then decreases, and then increases. The graph of the function passes through the points left-parenthesis negative 5 comma 0 right-parenthesis, left-parenthesis negative 2 comma 0 right-parenthesis, and left-parenthesis 0 comma 0 right-parenthesis.0, –2, –5 Image with alt text: assessment question 2 answer d As x increases, the function first increases, then decreases, and then increases. The graph of the function passes through the points left-parenthesis negative 5 comma 0 right-parenthesis, left-parenthesis negative 2 comma 0 right-parenthesis, and left-parenthesis 0 comma 0 right-parenthesis.
–2, –5, 2
assessment question 2 answer c
The correct answer is: –2, –5.
The graph of the function y = x(x + 2)(x + 5) will have x-intercepts at -2, -5, and 0.
The graph of the function y = x(x + 2)(x + 5) will have x-intercepts at -2, -5, and 0.
2 answers