To complete the ordered pairs based on the equation \( y = 14x \), we can substitute each \( x \) value to find the corresponding \( y \) value.
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For \( x = 0 \): \[ y = 14 \times 0 = 0 \] The ordered pair is \( (0, 0) \).
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For \( x = 4 \): \[ y = 14 \times 4 = 56 \] The ordered pair is \( (4, 56) \).
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For \( x = 8 \): \[ y = 14 \times 8 = 112 \] The ordered pair is \( (8, 112) \).
Now, completing the table:
\[ \begin{array}{|c|c|c|} \hline x & y & (x, y) \ \hline 0 & 0 & (0, 0) \ 4 & 56 & (4, 56) \ 8 & 112 & (8, 112) \ \hline \end{array} \]
So the completed ordered pairs are:
- \( (0, 0) \)
- \( (4, 56) \)
- \( (8, 112) \)