To determine the standard form of the equation of the line through the points given in the table, we first need to find the slope of the line and then use that to form the linear equation.
The points from the table are:
- (3, 11)
- (7, 8)
- (11, 5)
- (15, 2)
- (19, -1)
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Calculate the slope (m) using two points from the table: We can use points (3, 11) and (7, 8).
\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{8 - 11}{7 - 3} = \frac{-3}{4} = -\frac{3}{4} \]
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Use the point-slope form (y - y₁ = m(x - x₁)): Using the point (3, 11):
\[ y - 11 = -\frac{3}{4}(x - 3) \]
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Convert to standard form (Ax + By = C): Start with the point-slope form:
\[ y - 11 = -\frac{3}{4}x + \frac{9}{4} \]
Rearranging gives:
\[ y = -\frac{3}{4}x + \frac{9}{4} + 11 \]
Convert 11 to a fraction with a common denominator of 4:
\[ 11 = \frac{44}{4} \]
Therefore:
\[ y = -\frac{3}{4}x + \frac{53}{4} \]
To convert this to standard form (Ax + By = C), we can multiply through by 4 to eliminate the fraction:
\[ 4y = -3x + 53 \]
Rearranging gives:
\[ 3x + 4y = 53 \]
Thus, the standard form of the equation of the line is:
3x + 4y = 53.
Therefore, the correct response is: 3x + 4y = 53.