To solve the expression \((-\frac{3}{5}) \times (\frac{5}{16}) \times (\frac{7}{12}) \div (-\frac{3}{16}) \times (-\frac{5}{7})\), we will follow the order of operations and simplify step by step.
First, let's rewrite the division as multiplication by the reciprocal:
\[ (-\frac{3}{5}) \times (\frac{5}{16}) \times (\frac{7}{12}) \times (-\frac{16}{3}) \times (-\frac{7}{5}) \]
Now we can combine the negative signs:
\[ (- \times - \times -) = - \quad \text{(odd number of negatives)} \] This means the result will be negative.
Now we can multiply the fractions together. We can group the fractions for easier calculation:
\[ -\left(\frac{3 \times 5 \times 7 \times 16 \times 7}{5 \times 16 \times 12 \times 3}\right) \]
Now we will simplify:
-
The \(5\) in the numerator and denominator cancels out:
\[ 5 \text{ cancels with another } 5 \]
-
The \(16\) in the numerator and denominator cancels out:
\[ 16 \text{ cancels with the } 16 \]
-
The \(3\) in the numerator and denominator cancels out:
\[ 3 \text{ cancels with the } 3 \]
The expression now simplifies to:
\[ -\left(\frac{7 \times 7}{12}\right) = -\left(\frac{49}{12}\right) \]
Thus, the final result is:
\[ -\frac{49}{12} \]
So the answer is:
\[ \boxed{-\frac{49}{12}} \]