In the reaction, one H-H bond and one Cl-Cl bond are broken, and two H-Cl bonds are formed.
The total bond energy in the products can be calculated as follows:
Energy to break H-H bond: 435 kJ/mol
Energy to break Cl-Cl bond: 242 kJ/mol
Energy to form H-Cl bond (2 times): 427 kJ/mol
Total bond energy in products = (Energy to break H-H bond) + (Energy to break Cl-Cl bond) + (Energy to form H-Cl bond) x number of H-Cl bonds formed
= 435 kJ/mol + 242 kJ/smol + 427 kJ/mol x 2
= 677 kJ/mol + 854 kJ/mol
= 1531 kJ/mol
Therefore, the total bond energy in the products of the reaction is 1531 kJ/mol.
Question Use the information in the table to answer the question. Bond Bond Energy (kJ/mol) H–Cl 427 Cl–Cl 242 H–H 435 Hydrogen and chlorine gases react to produce hydrochloric acid according to the reaction. H2 + Cl2 → 2HCl How much total bond energy, in kJ/mol, is in the products of the reaction?
677 677 854 854 427 427 435
1 answer