To determine which labeled point is a viable solution for the inequality \( 25x + 15y \geq 200 \), we will substitute the coordinates of each point into the inequality.
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For the point \( (2, 3) \): \[ 25(2) + 15(3) = 50 + 45 = 95 \] Since \( 95 \not\geq 200 \), this point is not a viable solution.
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For the point \( (20, 11.5) \): \[ 25(20) + 15(11.5) = 500 + 172.5 = 672.5 \] Since \( 672.5 \geq 200 \), this point is a viable solution.
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For the point \( (10, 10) \): \[ 25(10) + 15(10) = 250 + 150 = 400 \] Since \( 400 \geq 200 \), this point is also a viable solution.
Out of the given options, both \( (20, 11.5) \) and \( (10, 10) \) are viable solutions. However, if you are asked to select only one, the point \( (20, 11.5) \) is certainly valid based on the calculations.
Thus, the answer is: (20, 11.5)