Asked by hudson
Question
Use the image to answer the question.
One solid and one dotted curve are drawn in a coordinate plane. The x-axis ranges from negative 3 to 3 and the y-axis ranges from negative 4 to 2, both by 1-unit increments.
Compare the graphs of f(x)=x+1−−−−√−2
and g(x)=x+1−−−−√3−2
. Identify which of the following features is true about the graphs.
(1 point)
Responses
The graphs have the same x-intercept.
The graphs have the same x -intercept.
The graphs have the same domains.
The graphs have the same domains.
The graphs have the same y-intercept.
The graphs have the same y -intercept.
The graphs have the same ranges.
The graphs have the same ranges.
Skip to navigation
Use the image to answer the question.
One solid and one dotted curve are drawn in a coordinate plane. The x-axis ranges from negative 3 to 3 and the y-axis ranges from negative 4 to 2, both by 1-unit increments.
Compare the graphs of f(x)=x+1−−−−√−2
and g(x)=x+1−−−−√3−2
. Identify which of the following features is true about the graphs.
(1 point)
Responses
The graphs have the same x-intercept.
The graphs have the same x -intercept.
The graphs have the same domains.
The graphs have the same domains.
The graphs have the same y-intercept.
The graphs have the same y -intercept.
The graphs have the same ranges.
The graphs have the same ranges.
Skip to navigation
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To compare the functions \( f(x) = \sqrt{x + 1} - 2 \) and \( g(x) = \sqrt{x + 1} + 3 - 2 \), we can analyze their features: x-intercepts, domains, y-intercepts, and ranges.
1. **X-intercepts**:
- To find the x-intercepts, set \( f(x) = 0 \) and \( g(x) = 0 \).
- For \( f(x) = \sqrt{x + 1} - 2 = 0 \):
\[
\sqrt{x + 1} = 2 \implies x + 1 = 4 \implies x = 3.
\]
- For \( g(x) = \sqrt{x + 1} + 1 = 0 \):
\[
\sqrt{x + 1} = -1 \text{ (not possible, since the square root cannot be negative)}.
\]
- Thus, the x-intercept of \( g(x) \) does not exist and is different from that of \( f(x) \).
2. **Domains**:
- Both functions contain \( \sqrt{x + 1} \), which requires \( x + 1 \geq 0 \) or \( x \geq -1 \).
- So the domain for both functions is \( x \geq -1 \).
3. **Y-intercepts**:
- To find the y-intercepts, evaluate \( f(0) \) and \( g(0) \):
- For \( f(0) \):
\[
f(0) = \sqrt{0 + 1} - 2 = 1 - 2 = -1.
\]
- For \( g(0) \):
\[
g(0) = \sqrt{0 + 1} + 3 - 2 = 1 + 1 = 2.
\]
- Thus, the y-intercepts are \( (-1) \) for \( f \) and \( (2) \) for \( g \), so they are different.
4. **Ranges**:
- The range of \( f(x) \):
\[
f(x) \text{ starts at } -1 \text{ and increases, approaching infinity. Thus, its range is } [-1, \infty).
\]
- The range of \( g(x) \):
\[
g(x) \text{ starts at } 2 \text{ and also increases, approaching infinity. Thus, its range is } [2, \infty).
\]
- Since the lowest values in their ranges are different, this means their ranges are also different.
### Conclusion:
The only feature that is true about the graphs is that they have the **same domains**. Therefore, the correct answer is:
**The graphs have the same domains.**
1. **X-intercepts**:
- To find the x-intercepts, set \( f(x) = 0 \) and \( g(x) = 0 \).
- For \( f(x) = \sqrt{x + 1} - 2 = 0 \):
\[
\sqrt{x + 1} = 2 \implies x + 1 = 4 \implies x = 3.
\]
- For \( g(x) = \sqrt{x + 1} + 1 = 0 \):
\[
\sqrt{x + 1} = -1 \text{ (not possible, since the square root cannot be negative)}.
\]
- Thus, the x-intercept of \( g(x) \) does not exist and is different from that of \( f(x) \).
2. **Domains**:
- Both functions contain \( \sqrt{x + 1} \), which requires \( x + 1 \geq 0 \) or \( x \geq -1 \).
- So the domain for both functions is \( x \geq -1 \).
3. **Y-intercepts**:
- To find the y-intercepts, evaluate \( f(0) \) and \( g(0) \):
- For \( f(0) \):
\[
f(0) = \sqrt{0 + 1} - 2 = 1 - 2 = -1.
\]
- For \( g(0) \):
\[
g(0) = \sqrt{0 + 1} + 3 - 2 = 1 + 1 = 2.
\]
- Thus, the y-intercepts are \( (-1) \) for \( f \) and \( (2) \) for \( g \), so they are different.
4. **Ranges**:
- The range of \( f(x) \):
\[
f(x) \text{ starts at } -1 \text{ and increases, approaching infinity. Thus, its range is } [-1, \infty).
\]
- The range of \( g(x) \):
\[
g(x) \text{ starts at } 2 \text{ and also increases, approaching infinity. Thus, its range is } [2, \infty).
\]
- Since the lowest values in their ranges are different, this means their ranges are also different.
### Conclusion:
The only feature that is true about the graphs is that they have the **same domains**. Therefore, the correct answer is:
**The graphs have the same domains.**
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.