To find the equation of a line in slope-intercept form, we first need to find the slope of the line using the two given points.
Slope (m) = (y2 - y1) / (x2 - x1)
= (-4 - 1) / (1 - 0)
= -5 / 1
= -5
Now that we have the slope, we can use one of the given points and the slope to plug into the slope-intercept form equation y = mx + b, where m is the slope and b is the y-intercept.
Using the point (0, 1):
1 = -5(0) + b
1 = b
Therefore, the equation of the line in slope-intercept form is y = -5x + 1.
Question
Use the image to answer the question.
An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid downward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma 1 right parenthesis and left parenthesis 1 comma negative 4 right parenthesis.
Write the equation of the line in slope-intercept form.
(1 point)
1 answer