Question

Question

Use the image to answer the question.

A line segment on a coordinate plane. The x-axis ranges from negative 2 to 5 in unit increments. The y-axis ranges from negative 3 to 3 in unit increments. The line extends downward from point upper A on the top left, to point upper B on the bottom right.

Calculate midpoint M of segment AB¯¯¯¯¯¯¯¯ .

(1 point)
Responses

M is located at (3,0).
upper M is located at left parenthesis 3 comma 0 right parenthesis .

M is located at (1.5,0).
upper M is located at left parenthesis 1.5 comma 0 right parenthesis .

M is located at (−2.5,2).
upper M is located at left parenthesis negative 2.5 comma 2 right parenthesis .

M is located at (0.5,1).
upper M is located at left parenthesis 0.5 comma 1 right parenthesis .
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Answer 1

To calculate the midpoint \( M \) of a line segment \( AB \) on a coordinate plane, we can use the midpoint formula:

\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]

where \( (x_1, y_1) \) are the coordinates of point \( A \) and \( (x_2, y_2) \) are the coordinates of point \( B \).

Without the coordinates for points \( A \) and \( B \) given in the question, I can't calculate the exact midpoint. However, if you know the coordinates of points \( A \) and \( B \), you just need to plug those values into the formula above to find the midpoint \( M \).

From the responses provided, it looks like potential midpoints include:

• \( M \) is located at \( (3, 0) \)
• \( M \) is located at \( (1.5, 0) \)
• \( M \) is located at \( (-2.5, 2) \)
• \( M \) is located at \( (0.5, 1) \)

Check which of these corresponds to the coordinates of \( A \) and \( B \) (if available), or if you can provide coordinates \( A \) and \( B \), I can help you calculate the midpoint directly.