To find the area of the tent's entrance, we need to calculate the area of the triangular portion and the rectangular portion separately and then add them together.
1. Triangular portion:
- Base: 6 meters
- Height: 3 meters
Area = 0.5 * base * height
Area = 0.5 * 6 * 3
Area = 9 square meters
2. Rectangular portion (twice):
- Length of each side: 6 meters
- Width: 3 meters
Area = length * width
Area = 6 * 3
Area = 18 square meters
Total for both sides = 18 + 18 = 36 square meters
Total area of the tent's entrance:
Triangular portion + Rectangular portion = 9 + 36 = 45 square meters
Therefore, the correct answer is:
45 m2
Question
Use the image to answer the question.
A 2-dimensional illustration of a building is shown with a pointed roofline and a large doorway in the center. The large doorway in the center of the baseline is 6 meters in length. The doorway is the same height as the vertical sides of the building, which is 3 meters. The left and right baselines on either side of the doorway measure 4 meters each. The height, drawn in a dashed line from the top center of the doorway to the triangular apex at the top of the building, is 3 meters.
An architect has drawn a blueprint of the entrance to a circus tent that will be built in Guildsville in a couple of weeks. Find the area of the tent’s entrance.
(1 point)
Responses
21 m2
21 m squared
45 m2
45 m squared
24 m2
24 m squared
66 m2
1 answer
5 answers